A particle moves in a straight line with a velocity $v$ $m s^{-1}$ given by \(v = 3t^2 - 4t - 8\

Question

A particle moves in a straight line with a velocity $v$ $m s^{-1}$ given by $v = 3t^2 - 4t - 8$, where $t$ is the time in seconds after passing a point $A$, which is $4$ metres to the left of a fixed point $O$.

Find the

acceleration when $t=4$.
The minimum velocity.
The average speed during the first $4$ seconds.

Accepted Answer

(a) $20\text{ m s}^{-2}$; (b) $-\dfrac{28}{3}\text{ m s}^{-1}$; (c) $\dfrac{80+56\sqrt7}{27}\text{ m s}^{-1}$

Kinematics - Maximum and Minimum Motion Quantities

Kinematics - Maximum and Minimum Motion Quantities

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