Find $\displaystyle\displaystyle\int 2 + \frac{6}{x^3} \ \mathrm{d}x$. Hence find the values of \(

Question

Find $\displaystyle\displaystyle\int 2 + \frac{6}{x^3} \ \mathrm{d}x$. Hence find the values of $k$ such that $\displaystyle\displaystyle\int_{k}^{2k} 2 + \frac{6}{x^3} \ \mathrm{d}x = 10$. Hint: Given that one of the values of $k$ is $0.5$.

Accepted Answer

(a) $2x-3/x^2+C$. (b) $k=\dfrac12,\ (9\pm3\sqrt{13})/4$.

Integration - Problems involving Unknowns

Integration - Problems involving Unknowns

Solution:

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