Find $\displaystyle\displaystyle\int 3x + \frac{1}{(x-5)^2} \mathrm{d}x$. Hence find the area of t

Question

Find $\displaystyle\displaystyle\int 3x + \frac{1}{(x-5)^2} \mathrm{d}x$. Hence find the area of the region bounded by the curve $y=3x+1/(x-5)^2$, the $x$-axis, the line $x = 2$ and the line $x = 4$.

Accepted Answer

(a) $\dfrac32x^2-\dfrac1{x-5}+C$; (b) $\dfrac{56}{3}\text{ units}^2$

Integration - Area Bounded by a Curve and Straight Lines

Integration - Area Bounded by a Curve and Straight Lines

Solution:

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