Kinematics - Differentiating Displacement and Velocity

Kinematics - Differentiating Displacement and Velocity

TGM Original Questions

A particle \(P\) moves in a straight line so that its displacement, \(s\) metres, from a fixed point \(O\), is given by \(s = t^3 - 2t^2 - 12t - 5\), where time \(t\) is the time taken in seconds after the start of motion. Calculate

  1. the initial velocity and acceleration,
  2. the value(s) of \(t\) when \(P\) is instantaneously at rest,
  3. the distance travelled in the first \(5\) seconds,
  4. the average speed of \(P\) during the first \(5\) seconds

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Answer:(a) Initial velocity \(-12\text{ m s}^{-1}\), initial acceleration \(-4\text{ m s}^{-2}\); (b) \(t=\dfrac{2+2\sqrt{10}}3\text{ s}\); (c) \(\dfrac{869+320\sqrt{10}}{27}\text{ m}\); (d) \(\dfrac{869+320\sqrt{10}}{135}\text{ m s}^{-1}\)

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