Cubed sine from a triple angle identity
Cubed sine from a triple angle identity
IB Year 6 | Grade 12
- Use complex number methods to show that \(\sin 3\theta = 3\sin\theta - 4\sin^3\theta\).
- Hence find the exact value of \(\sin^3\dfrac{5\pi}{12}\).
Video Solution:
Video solution locked
A free account saves your progress; this video needs tuition enrolment.
Solution:
Solution locked
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Answer:(a) Shown; \(\sin3\theta=3\sin\theta-4\sin^3\theta\) (b) \(\dfrac{3\sqrt6+5\sqrt2}{16}\)
Need help? Join our JC Math tuition classes.
Learn more