Cotangent squared in terms of a parameter
Cotangent squared in terms of a parameter
IB Year 6 | Grade 12
Given that \(\sec^2\theta=4p\), where \(0{}^\circ<\theta<90{}^\circ\), find \(\cot^2\theta\) in terms of \(p\).
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Answer:\(\cot^2\theta=\frac{1}{4p-1}\)
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