The vertices of triangle $ABC$ are $A(8,-5)$, $B(11,-4)$ and $C(1,k)$. Find the value of \(k

Question

The vertices of triangle $ABC$ are $A(8,-5)$, $B(11,-4)$ and $C(1,k)$. Find the value of $k$ if angle $ACB$ is $90$ degrees, the area of triangle $ABC$.

Accepted Answer

(a) $k = -6$ or $k = -3$ (b) Area = $\frac{5}{2}$ units$^2$ when $k = -3$, and $2$ units$^2$ when $k = -6$

Coordinate Geometry - Area of Rectilinear Figures

Coordinate Geometry - Area of Rectilinear Figures

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