Coordinate Geometry - Equation of a Straight Line
Coordinate Geometry - Equation of a Straight Line
TGM Original Questions
The point \(P\) has the coordinates of \((-3, 8)\) and the line joining the points \(P\) and \(Q\) has a gradient of \(-\frac{3}{4}\).
The perpendicular bisector of \(PQ\) passes through the point \((8, 6)\).
Find
- the equation of \(PQ\),
- the coordinates of \(Q\).
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Answer:(a) \(y = -\frac{3}{4}x + \frac{23}{4}\) (b) \(Q = (13,-4)\)
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