Coordinate Geometry - Perpendicular Bisectors
Coordinate Geometry - Perpendicular Bisectors
TGM Original Questions
The line \(y + 2x = 1\) intersects the curve \(x^2 - 2xy + y^2 = 8\) at \(P\) and \(Q\). Find
- the coordinates of \(P\) and \(Q\) in exact form,
- the equation of the perpendicular bisector \(PQ\).
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Answer:(a) \(\left(\frac{1\pm2\sqrt2}{3},\frac{1\mp4\sqrt2}{3}\right)\); (b) \(y=\frac12x+\frac16\).
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