Coordinate Geometry - Finding the Equation of a Circle
Coordinate Geometry - Finding the Equation of a Circle
TGM Original Questions
A circle with centre \(C\) passes through points \(A(-8, 3)\) and \(B(-1, -4)\).
- Explain why the perpendicular bisector of \(AB\) will pass through \(C\).
- Given that \(C\) lies on the line \(y = 2x + 5\), find \(C\).
- Hence find the equation of the circle.
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Answer:(a) \(CA=CB\), so \(C\) lies on the perpendicular bisector. (b) \((-1,3)\). (c) \((x+1)^2+(y-3)^2=49\).
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