The circle C_1 has equation x2+y2-4x-2y-4=0 and the circle C_2 has equation (x-5)2+(y-5)2=4. Show th

Question

The circle C_1 has equation x2+y2-4x-2y-4=0 and the circle C_2 has equation (x-5)2+(y-5)2=4. Show that C_1 and C_2 touch each other at exactly one point.

Accepted Answer

$d=5=r_1+r_2$, so the circles touch at exactly one point (externally tangent).

Showing two circles touch externally

Showing two circles touch externally

Solution:

Solution locked