The points $A$ is $\left( 1,12 \right)$ and $B$ is $\left( 7,-2 \right)$. Show that the equa

Question

The points $A$ is $\left( 1,12 \right)$ and $B$ is $\left( 7,-2 \right)$. Show that the equation of the line $AB$ is $7x+3y=43$. Write down the equation of the line which has the same gradient as the line $AB$ and passes through the point $C\left( 0,-2 \right)$.

Accepted Answer

(i) $3y + 7x = 43$ (ii) $y = -\frac{7}{3}x - 2$

Coordinate Geometry - Parallel and Perpendicular Lines

Coordinate Geometry - Parallel and Perpendicular Lines

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