<p>In the diagram, \(ABCD\) is a parallelogram.</p>
<p>The points \(P\) and \(Q\) lie on the diagonal \(AC\) such that \(\angle AQD = \angle BPC = 90{}^\circ\).</p>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/public/question-images/pasted/1767492462540-03w7widysk2g.png" style="max-width: min(300px, 100%); height: auto; display: block;" alt="Parallelogram ABCD with points P and Q on diagonal AC" class="aligncenter custom-width" /></figure></div>
<ol class="i-list"><li><div class="list-item-content"><span class="list-item-text">Prove that \(\Delta ADQ\) is congruent to \(\Delta CBP\).</span></div></li><li><div class="list-item-content"><span class="list-item-text">Name another pair of congruent triangles.</span></div></li></ol>

In the diagram, \(ABCD\) is a parallelogram.

The points \(P\) and \(Q\) lie on the diagonal \(AC\) such that \(\angle AQD = \angle BPC = 90{}^\circ\).

Prove that \(\Delta ADQ\) is congruent to \(\Delta CBP\).

Name another pair of congruent triangles.

Congruence Proofs within Parallelograms: A Study of $\triangle ADQ$ and $\triangle CBP$

Congruence Proofs within Parallelograms: A Study of $\triangle ADQ$ and $\triangle CBP$

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