Similarity proof in an extended parallelogram
Similarity proof in an extended parallelogram
Secondary 2
4 marks
TGM Original Questions
Optional extension
In the figure, \(ABCD\) is a parallelogram, \(E\) lies on \(DC\), and \(AE\) and \(BC\) are produced to meet at \(F\). Given \(DE:EC=2:3\):
- name a triangle similar to \(ADE\) and explain[2]
- show that \(BC=\frac25BF\).[2]
Solution:
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Answer:(i) \(\triangle FCE\), AAA (ii) \(BC/BF=2/5\).
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