In quadrilateral $ABCD$, $AB=AD=5\text{ cm}$ and $BC=CD=4\text{ cm}$. Prove that \(\angle

Question

In quadrilateral $ABCD$, $AB=AD=5\text{ cm}$ and $BC=CD=4\text{ cm}$. Prove that $\angle BAC=\angle CAD$.[4] Diagrams are not drawn to scale.

Accepted Answer

$\triangle ABC\equiv\triangle ADC$ (SSS), so $\angle BAC=\angle CAD$.

Congruence across a common diagonal