Conditional and exactly-two probabilities for three selections without replacement
Conditional and exactly-two probabilities for three selections without replacement
6 marks
A tray holds \(14\) milk chocolates and \(4\) dark chocolates. Three chocolates are taken from the tray at random, one at a time, and none is put back.
- Given that the first two chocolates taken are dark, find the probability that the third chocolate is milk.
- Find the probability that, of the three chocolates taken, exactly two are milk.
[6]
Solution:
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Answer:(a) \(\dfrac78\) (b) \(\dfrac{91}{204}\)
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