Concurrency of the Angle Bisectors of Triangles and the Incentre of Triangles

Concurrency of the Angle Bisectors of Triangles and the Incentre of Triangles

Incentre diagram of triangle ABC
Incentre diagram of triangle ABC

In triangle \(ABC\), \(AO\) and \(BO\) bisect angles \(BAC\) and \(ABC\), respectively. \(AO\) and \(BO\) intersect at \(O\).

  1. Prove the concurrency (intersecting at one point) of the \(3\) angle bisectors of a triangle by proving that \(CO\) bisects angle \(ACB\).
  2. Hence prove that there exists a circle with centre \(O\) that touches \(AB\), \(BC\) and \(AC\) at one point, respectively.

Note: The point \(O\) is known as the incentre of triangle \(ABC\) and \(O\) is equidistant to the \(3\) sides of triangle \(ABC\).

Solution:

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Answer:(i) \(CO\) bisects \(\angle ACB\), so the three internal bisectors concur at \(O\). (ii) The circle centred at \(O\), of radius \(OD=OE=OF\), touches all three sides.

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