Computation of expected value

Computation of expected value

IB Year 5 | Grade 11

The p.d.f. of a random variable \(X\) is given by

\(x\)\(-2\)\(-1\)\(0\)\(1\)\(2\)
\(\mathrm{P}(X = x)\)\(0.2\)\(0.1\)\(0.4\)\(0.1\)\(0.2\)

Find \(\mathrm{E}(X)\).

We observe that the symmetry of the p.d.f. leads to \(\mathrm{E}(X) = 0\).

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