Argand diagram transformations

It is given that
$z=\cos \theta +\mathbf{i}\sin \theta $, $-\pi \le \theta \le \pi $.
Show clearly that
$\frac{2}{1+z}=1-\mathbf{i}\tan \left( \frac{\theta }{2} \right)$.

$z=\cos \theta +\mathbf{i}\sin \theta $, $-\pi \le \theta \le \pi $.

$\frac{2}{1+z}=1-\mathbf{i}\tan \left( \frac{\theta }{2} \right)$.

Properties of Trigonometric and Exponential Forms

Complex Numbers

International Baccalaureate Mathematics: Analysis and Approaches Higher Level

Complex Numbers Q1

Complex Numbers Q1

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