Special Results involving Exponential Forms Q1
Special Results involving Exponential Forms Q1
Show that \(e^{\mathrm{i}\theta}-e^{-\mathrm{i}\theta}=2\mathrm{i}\sin \theta\).
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Answer:\( e^{i\theta} - e^{-i\theta} = 2i\sin\theta \) (shown)\)
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