The roots of the equation $x^{2}+(3\mathbf{i}-5)x+6-9\mathbf{i}=0$ are $\alpha$ and $\beta$, w

Question

The roots of the equation $x^{2}+(3\mathbf{i}-5)x+6-9\mathbf{i}=0$ are $\alpha$ and $\beta$, where $\alpha$ is a real number and $\beta$ is not a real number. Find $\alpha$ and $\beta$.

Accepted Answer

$\alpha=3,\ \beta=2-3\mathbf{i}$

Complex Numbers - Finding Roots of Equations with Complex Coefficients

Complex Numbers - Finding Roots of Equations with Complex Coefficients

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