Complex Numbers - Finding Square Roots of Complex Numbers Algebraically

Complex Numbers - Finding Square Roots of Complex Numbers Algebraically

Find the exact square roots of the complex number \(6\mathbf{i}\).

Hence, solve the quadratic equation \(z^{2} + 2\mathbf{i}z - 1 - 6\mathbf{i} = 0\).

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Answer: \(z=\sqrt{3}+\sqrt{3}\mathbf{i}\) or \(-\sqrt{3}-\sqrt{3}\mathbf{i}\); \(z=\sqrt{3}+(\sqrt{3}-1)\mathbf{i}\) or \(-\sqrt{3}-(\sqrt{3}+1)\mathbf{i}\)

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