Special Results involving Exponential Forms Q6
Special Results involving Exponential Forms Q6
Express \(2+2e^{i\theta}\) in the form \(r{\mathrm{e}}^{\mathbf{i},\alpha}\) exactly, where \(-\pi <\alpha \le \pi\).
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Answer:\( 2 + 2e^{i\theta} = \left(4\cos\frac{\theta}{2}\right)e^{i\frac{\theta}{2}} \)
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