Express $6-2x-{{x}^{2}}$ in the form of $p-{{(x-q)}^{2}}$ , where $p$ and $q$ are const

Question

Express $6-2x-{{x}^{2}}$ in the form of $p-{{(x-q)}^{2}}$ , where $p$ and $q$ are constants. Hence, solve the equation $6-2x-{{x}^{2}}=0$ giving your answers correct to $2$ decimal places.

Accepted Answer

(i) $7-{{\left( x+1 \right)}^{2}}$ (ii) $x = 1.65$ or $x = -3.65$ (2 d.p.)

Completing the Square with Negative Quadratics

Completing the Square with Negative Quadratics

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