Complementary angles from a sine difference

Complementary angles from a sine difference

IB Year 6 | Grade 12

Two complementary angles \(x\) and \(y\) are such that \(\sin(x-y)=\dfrac{1}{2}\). Given that \(x>y\), find the values of \(x\) and \(y\) in degrees.

Solution:

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Answer:\(x=60{}^\circ,\ y=30{}^\circ\)

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