Coefficients of a cubic in terms of its roots, and the constant term when the roots are in arithmetic or geometric progression

Coefficients of a cubic in terms of its roots, and the constant term when the roots are in arithmetic or geometric progression

IB Year 6 | Grade 12
14 marks

The roots of the cubic equation \(x^3+ax^2+bx+k=0\) are \(\alpha\), \(\beta\) and \(\gamma\). Expand \((x-\alpha)(x-\beta)(x-\gamma)\) and compare coefficients to show that

    1. \(a=-(\alpha+\beta+\gamma)\)
    2. \(b=\alpha\beta+\beta\gamma+\gamma\alpha\)
    3. \(k=-\alpha\beta\gamma\).[3]

In the rest of this question, \(a=-9\) and \(b=36\).

    1. Suppose that \(\alpha\), \(\beta\) and \(\gamma\) are consecutive terms of an arithmetic sequence. Show that \(3\) is a root of the equation.
    2. Hence find \(k\).[5]
  1. Suppose instead that \(\alpha\), \(\beta\) and \(\gamma\) are consecutive terms of a geometric sequence. Find \(k\).[6]

Solution:

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Answer:(a) \(a=-(\alpha+\beta+\gamma)\), \(b=\alpha\beta+\beta\gamma+\gamma\alpha\), \(k=-\alpha\beta\gamma\) (b)(i) the middle root is \(3\) (b)(ii) \(k=-54\) (c) \(k=-64\)

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