Checking the side-of-chord condition

Checking the side-of-chord condition

Secondary 4
3 marks
TGM Original Questions

Points \(C\) and \(E\) lie on opposite sides of chord \(AB\), on the circle. \(\angle ACB=37^\circ\). A pupil says that \(\angle AEB=37^\circ\) because both angles stand on chord \(AB\).

  1. Explain why the pupil cannot use the same-segment property.[1]
  2. Find \(\angle AEB\), giving a reason.[2]

Solution:

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Answer:(a) Opposite sides of the chord (b) \(143^\circ\)

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