When \(y=kx^n\), multiplying \(x\) by a factor \(r\) multiplies \(y\) by \(r^n\). The constant \(k\) cancels, so the change in \(y\) can be found without knowing \(k\).
Why: new \(y=k(rx)^n=r^n\left(kx^n\right)=r^n\times\text{original}\hspace{0.5em}y\).
| Change in \(x\) | Multiplier for \(x\) | \(y=kx\) | \(y=kx^2\) | \(y=kx^3\) |
|---|---|---|---|---|
| doubled | \(2\) | \(\times2\) | \(\times4\) | \(\times8\) |
| halved | \(0.5\) | \(\times0.5\) | \(\times0.25\) | \(\times0.125\) |
| increased by \(50\%\) | \(1.5\) | \(\times1.5\) | \(\times2.25\) | \(\times3.375\) |
| decreased by \(20\%\) | \(0.8\) | \(\times0.8\) | \(\times0.64\) | \(\times0.512\) |
Method
Example
The power, \(P\) watts, produced by a wind turbine is directly proportional to the cube of the wind speed, \(v\) m/s. The wind speed increases by \(20\%\). Find the percentage increase in \(P\).
Multiplier for \(v\): \(1.2\)
Multiplier for \(P\): \(1.2^3=1.728\)
Increase: \((1.728-1)\times100\%=72.8\%\)
Check: a \(20\%\) increase in \(v\) does not give a \(60\%\) increase in \(P\); the multiplier is cubed, not the percentage. Test with numbers: \(v=10\) gives \(P=1000k\); \(v=12\) gives \(P=1728k\), which is \(72.8\%\) more.
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