2026 CJC Promo Q3

2026 CJC Promo Q3

Junior College 1
6 marks
Promo

Referred to the origin \(O\), the points \(A\) and \(B\) have position vectors \(\mathbf a\) and \(\mathbf b\) respectively. It is given that \(|\mathbf a|=\sqrt2|\mathbf b|\) and \(\mathbf a\) is perpendicular to \(\mathbf b\). The point \(P\) lies on \(AB\) such that \(AP:PB=2:1\).

  1. Show that \(OP\) is perpendicular to \(AB\).[3]

It is now given that \(|\mathbf b|=2\).

  1. Find the exact length of \(OP\).[3]

Solution:

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Answer:(a) \(\overrightarrow{OP}\cdot\overrightarrow{AB}=0\). (b) \(\dfrac{2\sqrt6}{3}\).

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