Core stretch Triangle $RST$ is right-angled at $S$. Point $M$ is the midpoint of $ST$, and \

Question

Core stretch Triangle $RST$ is right-angled at $S$. Point $M$ is the midpoint of $ST$, and $MN\perp RT$. Prove that $TN^2+RS^2=RN^2$. $R$ $S$ $T$ $M$ $N$

Accepted Answer

$TN^2+RS^2=RN^2$, as required.

A midpoint-projection Pythagorean identity

A midpoint-projection Pythagorean identity

Solution:

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