Rearranging powers and reciprocals

Rearranging powers and reciprocals

Secondary 2

3 marks

TGM Original Questions

Make \(d\) the subject of \(b=\dfrac{kd^3-e}{3}\).[3]

Assume \(k\ne0\).

Solution:

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Answer:\(d=\sqrt[3]{\dfrac{3b+e}{k}}\)

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