Let $c_2$ and $c_3$ be the coefficients of $x^2$ and $x^3$ respectively in $(1-2x)^8$

Question

Let $c_2$ and $c_3$ be the coefficients of $x^2$ and $x^3$ respectively in $(1-2x)^8$. Find $\dfrac{c_3}{c_2}$. Find $\dfrac{c_3x^3}{c_2x^2}$, for $x\ne0$. When $x=\dfrac14$, are these two terms equal, opposite, or neither? Explain.

Accepted Answer

(a) $-4$; (b) $-4x$; (c) Opposite.

Binomial Theorem

Binomial Theorem

Solution:

Solution locked