Maclaurin Series and Power Series - Approximations Using Power Series

Maclaurin Series and Power Series - Approximations Using Power Series

IP 4

Expand \({{\left( 1-2x \right)}^{8}}\) in ascending powers of \(x\), up to and including the term \({{x}^{3}}\). Hence, evaluate \({{\left( 0.96 \right)}^{8}}\), correct to \(3\) decimal places.

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Answer:\(1-16x+112x^2-448x^3+\cdots\) \(0.721\)

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