Suppose \(n \in \mathbb{Q}\). The Binomial Theorem can be generalized to the following:
\[(a+b)^n = a^n \left( 1 + n \left( \frac{b}{a} \right) + \frac{n(n-1)}{2!} \left( \frac{b}{a} \right)^2 + \dots \right)\]
Notes:
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