Given that $X\sim\mathrm{B}(25,0.35)$, find $\mathrm{P}(X=10)$ $\mathrm{P}(X12)$ $\mathrm{P}(8.12 $

Question

Given that $X\sim\mathrm{B}(25,0.35)$, find $\mathrm{P}(X=10)$ $\mathrm{P}(X>12)$ $\mathrm{P}(8.12 $\mathrm{P}(X\ge 17.3)$ $\mathrm{P}\left( \left| X-10 \right|$\mathrm{P}(\left| X-12 \right|>3)$ Probability that $X$ lies within one standard deviation from the mean. Mode of $X$.

Accepted Answer

(i) $0.141$ (ii) $0.0604$ (iii) $0.524$ (iv) $0.000181$ (v) $0.99966$ (vi) $0.470$ (vii) $0.701$ (viii) Mode = 9

Worked Example 2

Worked Example 2

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