An improper fraction has numerator $n$ and denominator $d$. If $1$ is subtracted from its nume

Question

An improper fraction has numerator $n$ and denominator $d$. If $1$ is subtracted from its numerator and $1$ is added to its denominator, it becomes $\frac{3}{2}$. If $1$ is added to its numerator and its denominator is doubled, it becomes $1$.

Accepted Answer

(a) $2(n-1)=3(d+1),n+1=2d$ (b) $n=13,d=7$ (c) $\dfrac{13}{7}$

Fraction transformations

Fraction transformations

Solution:

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