For two real numbers $x$ and $y$, where $y\ne0$, given that $x$ is $40\%$ of \(y

Question

For two real numbers $x$ and $y$, where $y\ne0$, given that $x$ is $40\%$ of $y$, find the value of $\frac{x}{8y}$, $(5x + y)$ as a percentage of $y$, $x^2$ as a percentage of $y^2$, $y^2$ as a percentage of $x^2$.

Accepted Answer

(i) $\frac{1}{20}$ (ii) $300\%$ (iii) $16\%$ (iv) $625\%$

Basics of Percentage

Basics of Percentage

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