Two horizontal beams, $AB$ and $CD$, are parallel. Braces $PQ$ and $PR$ form a triangle betw

Question

Two horizontal beams, $AB$ and $CD$, are parallel. Braces $PQ$ and $PR$ form a triangle between them. Points $A,P,B$ lie on a straight line, and $C,Q,R,D$ lie on another straight line. The brace $QP$ is extended beyond $P$ to $X$. It is given that$$\angle XPB=58^\circ,\qquad \angle BPR=34^\circ.$$ Find the following angles, giving reasons for your answers. $\angle APQ$. [1] $\angle PQR$. [1] $\angle QPR$. [2] Reflex $\angle PRQ$. [2]

Accepted Answer

(a) $58^\circ$ (b) $58^\circ$ (c) $88^\circ$ (d) $326^\circ$

Basic Geometry - Angles

Basic Geometry - Angles

Solution:

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