Approximating trigonometrical functions
Approximating trigonometrical functions
IB Year 6 | Grade 12
Prove that \(\sin\left(\frac{\pi}{6} + x\right) \approx \frac{1}{2} + \frac{1}{2}\sqrt{3}x - \frac{1}{4}x^2 + \dots\)
Solution:
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Answer:\(\sin\!\left(\dfrac\pi6+x\right)\approx\dfrac12+\dfrac{\sqrt3}{2}x-\dfrac{x^2}{4}\) for small \(x\) (shown).
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