<p>Given that&nbsp;$AB=9$cm, the radius of the circle $OA=20.5$cm and $\angle ABC=90{}^\circ $. Find,</p>
<ol class="i-list"><li><div class="list-item-paragraph">the area of triangle $ABC$,</div></li><li><div class="list-item-paragraph">$h$, the perpendicular distance from point $B$ to the line $AC$.</div></li></ol>
<div class="content-block"><figure class="question-figure aligncenter" style="text-align: center;"><img src="https://vocwkpgapvksartxhhor.supabase.co/storage/v1/object/public/question-images/pasted/1765175081836-h30q86g9z7v.png" style="max-width: min(350px, 100%); height: auto; display: block;" class="aligncenter custom-width" /></figure></div>

Given that $AB=9$cm, the radius of the circle $OA=20.5$cm and $\angle ABC=90{}^\circ $. Find,

$h$, the perpendicular distance from point $B$ to the line $AC$.

Applying Pythagoras in a Circle-Based Triangle

Applying Pythagoras in a Circle-Based Triangle

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