Applications of Integration - Riemann Sums

Applications of Integration - Riemann Sums

8 marks

In this question, \(a\) is a positive constant.

  1. Explain, with the aid of a sketch, why \(\frac{a}{n} \sum_{k=1}^{n} \ln \left(1 + \frac{ak}{n}\right) > \int_{0}^{a} \ln(1+x) \, \mathrm{d}x\) for all positive integers \(n\).[2]
  2. State a similar expression that is less than \(\int_{0}^{a} \ln(1+x) \, \mathrm{d}x\).[1]
  3. Use your sketch in part (i) to explain why \(\lim_{n \to \infty} \left[ \frac{a}{n} \sum_{k=1}^{n} \ln \left(1 + \frac{ak}{n}\right) \right] = \int_{0}^{a} \ln(1+x) \, \mathrm{d}x\) and find the value of this limit exactly in terms of \(a\).[5]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(i) The right Riemann sum is greater than the integral (ii) \(\dfrac an\sum_{k=0}^{n-1}\ln\left(1+\dfrac{ak}{n}\right)<\displaystyle\int_0^a\ln(1+x)\,\mathrm dx\) (iii) \((a+1)\ln(a+1)-a\)

Need help? Join our JC Math tuition classes.

Learn more