Express $\displaystyle\int\nolimits_{1}^{\infty }{x{{e}^{-2x}}\,\mathrm{d}x}$in the form of \(a+b{

Question

Express $\displaystyle\int\nolimits_{1}^{\infty }{x{{e}^{-2x}}\,\mathrm{d}x}$in the form of $a+b{{e}^{-2}}$ where $a$ and $b$ are constants to be determined.

Accepted Answer

$a=0$, $b=\frac{3}{4}$

Applications of Intergration - Integration as an Inverse Process of Differentiation

Applications of Intergration - Integration as an Inverse Process of Differentiation