Let \(f(x) = \frac{\ln{5x}}{kx}\) where \(x > 0, k \in \mathbb{R}^+\).
Show that \(f'(x) = \frac{1 - \ln{5x}}{kx^2}\).
[3]The graph of \(f\) has exactly one maximum point \(\mathrm{P}\)
Find the \(x\)-coordinate of \(\mathrm{P}\).
[3]The second derivative of \(f\) is given by \(f''(x) = \frac{2\ln{5x} - 3}{kx^3}\). The graph of \(f\) has exactly one point of inflexion \(\mathrm{Q}\).
Show that the \(x\)-coordinate of \(\mathrm{Q}\) is \(\frac{1}{5}\mathrm{e}^{\frac{3}{2}}\).
[3]The region \(R\) is enclosed by the graph of \(f\), the \(x\)-axis, and the vertical lines through the maximum point \(\mathrm{P}\) and the point of inflexion \(\mathrm{Q}\).
Given that the area of \(R\) is \(3\), find the value of \(k\).
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