Rectangle under an implicit curve

Rectangle under an implicit curve

Junior College 1
9 marks

Rectangle \(OPQR\) has sides parallel to the coordinate axes, with \(O\) at the origin, \(P\) on the positive \(x\)-axis and \(R\) on the positive \(y\)-axis. The vertex \(Q(x,y)\) lies in the first quadrant on the curve \(C\), whose equation is \(x^2+2xy+4y^2=52\). The variables \(x\) and \(y\) are measured in units. Let \(A\) be the area of the rectangle.

  1. Find \(\frac{\mathrm{d}y}{\mathrm{d}x}\) in terms of \(x\) and \(y\).[2]
  2. Hence, show that \(A\) has a stationary value when \(x=2y\), and find the exact maximum value of \(A\).[4]
  3. At an instant, \(Q=(6,1)\) and \(x\) is increasing at a constant rate of \(\frac{5}{2}\) units/s. Find the rate of change of \(A\) at this instant.[3]

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Answer:(i) \(\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{x+y}{x+4y}\) (ii) \(A_{\max}=\frac{26}{3}\text{ units}^2\) (iii) \(\frac{\mathrm{d}A}{\mathrm{d}t}=-8\text{ units}^2\text{/s}\) (decreasing)

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