Sketch the parametric curve $x = 2t^{2} - 1$, $y = 3(t + 1)$ for $t \in \mathbb{R}$. Find

Question

Sketch the parametric curve $x = 2t^{2} - 1$, $y = 3(t + 1)$ for $t \in \mathbb{R}$. Find the coordinates of the points of intersection of the curve in (i) and the straight line $3x - 4y = 3$.

Accepted Answer

(i) $x=\frac29(y-3)^2-1$, a right-opening parabola with vertex $(-1,3)$ (ii) $(1,0)$ and $(17,12)$

Graphing Techniques - Sketching Parametric Curves

Graphing Techniques - Sketching Parametric Curves

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