Find the equation of the normal to the curve $y = 3x^2 + 5x - 9$ at the point where \(x = -2\

Question

Find the equation of the normal to the curve $y = 3x^2 + 5x - 9$ at the point where $x = -2$, hence find the $y$-coordinate of the point where this normal meets the curve again.

Accepted Answer

Normal: $y=\dfrac17x-\dfrac{47}{7}$; other $y$-coordinate: $-\dfrac{979}{147}$

Differentiation - Tangents and Normals at a Point

Differentiation - Tangents and Normals at a Point

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