Water is poured into an initially empty hemispherical bowl of radius \(12\) cm at a constant rate of \(6\pi\) \(\text{cm}^3 / \text{s}\). The volume of water in the bowl, \(V\) \(\text{cm}^3\), is given by \(V = \frac{1}{3} \pi x^2 (36 - x)\), where \(x\) is the depth of water (in cm) directly below the centre.
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