The parametric equations of a curve are $x = \frac{t}{1 - t^{3}}$ and $y = \frac{1}{1 - t^{3}}$,

Question

The parametric equations of a curve are $x = \frac{t}{1 - t^{3}}$ and $y = \frac{1}{1 - t^{3}}$, where $t \ne 1$. Find the equation of the normal to the curve at the point where $t = 2$.

Accepted Answer

$y=-\frac{17}{12}x-\frac{23}{42}$

Techniques of Differentiation - Quotient Rule

Techniques of Differentiation - Quotient Rule

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