<p>The gradient of a curve by \(\frac{\mathrm{d}y}{\mathrm{d}x} = 4\cos{x} - \sin{x}\). The curve passes through the point \( (\pi, 3)\). Find the equation of the curve.<span class="inline-marks">[5]</span></p>

The gradient of a curve by \(\frac{\mathrm{d}y}{\mathrm{d}x} = 4\cos{x} - \sin{x}\). The curve passes through the point \( (\pi, 3)\). Find the equation of the curve.

Applications of Differentiation

International Baccalaureate Mathematics: Analysis and Approaches Standard Level

2025 Nov TZ3 P1 Q2

2025 Nov TZ3 P1 Q2