A curve is such that $\frac{\mathrm{d}y}{\mathrm{d}x} = 4x - hx^2$ where $h$ is a cons

Question

A curve is such that $\frac{\mathrm{d}y}{\mathrm{d}x} = 4x - hx^2$ where $h$ is a constant. Given that the curve has a turning point at $(4, 5)$, show that the value of $h$ is $1$. find the range of values of $x$ for which $y$ is an increasing function.

Accepted Answer

(a) $h=1$ (b) $0<x<4$

Differentiation - Increasing and Decreasing Functions

Differentiation - Increasing and Decreasing Functions

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